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Matplotlib DPL94 R1rho R2eff
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10:46, 16 March 2014
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Here the calculated value is noted as: R_eff. : Equation 27:
$$ R_{eff} = R_{1\rho} / sin^2(\theta) - R_1 / tan^2(\theta) = R^{0}_2 + R_{ex} $$
Where $R^{0}_2$ refers to
R1rho_prime
$R_{1\rho '}
as seen at [[DPL94]]
Ref [3], Equation 20.
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