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B14
,<math>
\cosh{\left(\tau_{\textrm{CP}}E_2\right)} = \cos{\left(\tau_{\textrm{CP}}|E_2|\right)} \\
\sinh{\left(\tau_{\textrm{CP}}E_2\right)} = i \sin{\left(\tau_{\textrm{CP}}|E_2|\right)}
</math>
=== Equation compared to Carver Richards 72 ===