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Matplotlib DPL94 R1rho R2eff

51 bytes added, 10:50, 16 March 2014
Ref [2], Equation 27.
Here the calculated value is noted as: $R_{eff}$. : Equation 27: $$ R_{eff} = R_{1\rho} / sin^2(\theta) - R_1 / tan^2(\theta) = R^{0}_2 + R_{ex} $$. <br>
Where $R^{0}_2$ refers to $R_{1\rho '}$ as seen at [[DPL94]]
Ref [3], Equation 20.
Here the calculated value is noted as: $R_2$: $R_2 = R{1_\rho} / sin^2(\theta) - R_1 / tan^2(\theta)$<br>
Figure 11+16, would be the reference.
Ref [4], Equation 43.R_eff $R_{eff} = R1rho R_{1\rho} / sin^2(\theta) - R_1 / tan^2(\theta)$
Ref [5], Material and Methods, page 740.Here the calculated value is noted as: $R_2: R_2 = R^{0}_2 + R_exR_{ex}$.<br>
Figure 4 would be the wished graphs.
A little table of conversion then gives
<source lang="text">
Relax equation | Relax store | Articles
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R1rho' spin.r2 R^{0}_2 or Bar{R}_2Fitted pars Not stored R_exR1rho spin.r2eff R1rhoR_1 spin.ri_data['R1'] R_1 or Bar{R}_1</source>
 The parameter is called '''R_2 ''' or '''R_eff '' in the articles.
Since reff is not used in relax, this could be used?
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