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</math>
Expressing in terms of $\textrm{w}_\textrm{1}, \textrm{w}_\textrm{eff}$<br>
<math>
\frac{\Phi_\textrm{ex} \textrm{k}_\textrm{ex}}{\textrm{k}_\textrm{ex}^2 + \omega_\textrm{e}^2} \right) \sin^2\theta
</math>
