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Expressing in terms of $\textrm{w}_\textrm{1}, \textrm{w}_\textrm{eff}$ <br>
<math>
\sin^2\theta \left( \frac{\Phi_\textrm{ex} \textrm{k}_\textrm{ex}}{\textrm{k}_\textrm{ex}^2 + \omega_\textrm{e}^2} \right)= \frac{w_\textrm{1}^2}{w_\textrm{eff}^2}
</math>
